Given that at 25.0 ∘c ka for hcn is 4.9×10−10 and kb for nh3 is 1.8×10−5, calculate kb for cn− and ka for nh4+. enter the kb value for cn− followed by the ka value for nh4+, separated by a comma, using two significant figures.

Explanation:

Using the expression :

Where, is the dissociation constant of water.

At ,

Thus, for HCN ,

for CN⁻ can be calculated as:

Thus, for NH₃ ,

for can be calculated as:

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

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