Consider the reaction c12h22o11 (s) + 12 o2 (g) → 12 co2 (g) + 11 h2o (l) in which 10.5 g of sucrose, c12h22o11, was burned in a bomb calorimeter with a heat capacity of 7.50 kj/oc (including its water). the temperature inside the calorimeter was found to increase by 20.2 oc. based on this information, what is the heat of this reaction per mole of sucrose?

The heat of reaction is 4938 kJ/mole

Explanation:

It is possible to calculate the heat of a reaction using:

For the reaction:

C₁₂H₂₂O₁₁ (s) + 12 O₂ (g) → 12 CO₂ (g) + 11 H₂O (l)

Specific heat: 7,50kJ/°C

dT = 20,2°C

Thus, q = 151,5 kJ

The moles of sucrose are: 10,5g /342,2965 g/mol = 0,030675 moles

The heat of reacton is:

I hope it helps!

answer; talc and gypsum;

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.