Calculate the amount, in moles, of each of the following. you may round atomic masses to one decimal place.
3.29 g cds =
17.5 g moo3 =
890 g alpo4 =

The answer to your question is:

a) 0.023 mol of CdS

b) 0.12 mol of MoO3

c) 7.3 mol of AlPO4

Explanation:

a) CdS

MW = 112.4 + 32

      = 144 g

                                144g 1 mol

                                  3.28g  x

                                 x = (3.28 x 1) / 144

                                 x = 0.023 mol

b) MoO3

MW = 96 + 3(16) = 144 g

                              144g  1 mol

                               17.5g   x

                               x = (17.5 x 1) / 144

                               x = 0.12 mol

c) AlPO4

MW = 27 + 31 + 4(16)

MW = 122 g

                            122 g  1mol

                            890 g   x

                            x = (890 x 1) / 122

                            x = 7.3 mol of AlPO4

i just got this problem. it's 90.3

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots