The reaction of 60.0 g of aluminum oxide with 30.0 g of carbon produced co gas and 22.5 g of aluminum metal. what is the percent yield aluminum for this reaction?

The percent yield of aluminum for this reaction is 70.9%.G

Given:

The reaction of 60.0 g of aluminum oxide with 30.0 g of carbon produced CO gas and 22.5 g of aluminum metal.

To find:

The percent yield of aluminum for this reaction.

Solution:

Mass of aluminum oxide = 60.0 g

Moles of aluminum oxide =

Mass of carbon = 22.5 g

Moles of carbon

According to reaction, 1 mole of aluminum oxide reacts with 3 moles of carbon, then 0.588 moles of aluminum oxide will react with:

0.588 moles of aluminum oxide react with 1.764 moles of carbon.

This indicates that:

According to reaction, 1 mole of aluminum oxide gives 2 moles of aluminum, then 0.588 moles of aluminum oxide will give:

Mass of 1.176 moles of aluminum :

The theoretical yield of the reaction = 31.73 g

The experimental yield of the reaction = 22.5 g

The percent yield of the reaction :

The percent yield of aluminum for this reaction is 70.9%.

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The answer to your question is: 70.8%

Explanation:

Data

Al₂O₃ = 60 g

C = 30 g

CO = gas

Al = 22.5 g

MW Al₂O₃ = 102 g

MW C = 12 g

MW Al = 54 g

Reaction

                 Al₂O₃    +     3C     ⇒       3 CO    +    2 Al

Limiting reactant

                            102 g of Al₂O₃  -------------- 54 g Al

                             60 g                 --------------   x

                             x = 31.8 g

                            36 g of C ------------------ 54 g of Al

                            30 g of C ------------------  x

                            x = 45 g of Al

Limiting reactant = Al₂O₃

Percent yield =

Percent yield = 70.75 %

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.