Aluminum had a specific heat of 0.215 cal/(g °c). when 25.7 cal (108.5 j) of heat is added to 18.4 g of aluminum at 20.0°c, what is the final temperature of the aluminum?

26.5°C

Explanation:

Heat added is the product of mass, specific heat capacity, and change in temperature.

q = mC(T − T₀)

25.7 cal = (18.4 g) (0.215 cal/g/°C) (T − 20.0°C)

T = 26.5°C

indium, and thallium have three electrons i think

solute : a solute is a substance that is dissolved in another substance is known as a solvent. it is mixed with a special mixture know as homogeneous mixture.

solvent: a solvent is a substance that dissolved a solute, which results in a solution is known as solvent.