Calculate the number of grams of solute needed to make each of the following solutions:
100 g of 0.500% (w/w) nai
250 g of 0.500% (w/w) nabr
500 g of 1.25% (w/w) c6h12o6 (glucose)
750 g of 2.00% (w/w) h2so4

Explanation:

(w/w) % : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

1) 100 g of 0.500% (w/w) NaI

Mass of solution = 100 g

Mass of solute = x

Required w/w % of solution = 0.500%

0.500 grams of solute needed to make 100 g of 0.500% (w/w) NaI.

2) 250 g of 0.500% (w/w) NaBr

Mass of solution = 250 g

Mass of solute = x

Required w/w % of solution = 0.500%

1.25 grams of solute needed to make 250 g of 0.500% (w/w) NaBr

3) 500 g of 1.25% (w/w) glucose

Mass of solution = 500 g

Mass of solute = x

Required w/w % of solution = 1.25%

6.25 grams of solute needed to make 500 g of 1.25% (w/w) (glucose)

4) 750 g of 2.00% (w/w) sulfuric acid.

Mass of solution = 750 g

Mass of solute = x

Required w/w % of solution = 2.00%

15.0 grams of solute needed to make 750 g of 2.00% (w/w) sulfuric acid.

i believe it is 40–40–20%

explanation:

answer; 4 electrons;