The enthalpy of fusion for benzene (c6h6, 78.0 g/mol) is 127.40 kj/kg, and its melting point is 5.5°c. what is the entropy change when 1 mole of benzene melts at 5.5°c? (show all unit conversions and write out all equations)

35.662 J/K is the entropy change when 1 mole of benzene melts at 5.5°C

Explanation:

The enthalpy of fusion for benzene =

Molar mass of benzene = 78.0 g/mol

Or can be written as 1 mole of benzene = 78.0 g

1 g of benzene  =

= 127.40 kJ/kg=127.40 kJ/1000 g (1kg = 1000 g)

= 9.9372 kJ/mol = 9937.2 J /mol

The entropy change when 1 mole of benzene melts at 5.5°C:

T = 5.5°C = 278.65 K

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !