sort each isotope based on the abundance of isotopes on earth, as shown in the phet simulation by selecting nature's mix, and on planet x given the following information: average atomic mass values for planet x (amu) oxygen 16.09 chlorine 36.97 boron 10.31 although there are three isotopes for oxygen, you only need to sort the two listed.

drag the appropriate items to their respective bins.

1. o-16

2. o-18

3. cl-37

4. b-11

5. cl-35

6. b-10

choices (bins of categorization which 1-6 must be separated into)

a. more abundant on earth

b. more abundant on planet x

c. approximately equal abundance on both.

1. O-16  : More abundant on planet X

2. O-18 :  More abundant on Earth

3. Cl-37 : More abundant on planet X

4. B-11  :  : More abundant on Earth

5. Cl-35 : More abundant on Earth

6. B- 10 : More abundant on planet X

Explanation:

Average atomic mass is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

1. O-16  : More abundant on planet X

Average atomic mass of oxygen = 16.09 amu

As, the average atomic mass of oxygen is closer to the mass of O-16 isotope. This means that the relative abundance of O-16 isotope is the higher as compared to the other isotopes on planet X.

2. O-18 :  More abundant on Earth

3. Cl-37 : More abundant on planet X

Average atomic mass of chlorine = 36.97 amu

As, the average atomic mass of chlorine is closer to the mass of Cl-37 isotope. This means that the relative abundance of Cl-37 isotope is the higher as compared to the other isotopes on planet X.

4. B-11  : More abundant on Earth

Average atomic mass of boron = 10.31 amu

As, the average atomic mass of boron is closer to the mass of B-10 isotope. This means that the relative abundance of B-10 isotope is the higher as compared to the other isotopes on planet X.

5. Cl-35 : More abundant on Earth

6. B- 10 : More abundant on planet X

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"