A1.00 cm2 blackbody surface emits 201 watts of radiant power. what is the temperature of the surface? give to the nearest whole degree.

Explanation:

Formula for black body radiation is as follows.

where,       P = power emitted

                 A = surface area of black body

          = Stephen's constant =

As area is given as 1.0 . Converting it into meters as follows.

                 (as 1 m = 100 cm)

            =

It is given that P = 201 watts. Hence,  

        =

                =

                       T =

                          = 8862.5 K

Thus, we can conclude that the temperature of the surface is 8862.5 K.

law of conservation of matter