What is the molarity of zncl2 that forms when 30.0 g of zinc completely reacts with cucl2 according to the following reaction? assume a final volume of 270 ml . zn(s)+cucl2(aq)→zncl2(aq)+cu(s)

The molarity of ZnCl2 is 1.699 mol/ L.

Explanation:

Balance chemical equation:

Zn(s) + CuCl2(aq) → ZnCl2(aq) + Cu(s)

Given data:

mass of zinc = 30 g

total volume of solution = 270 mL

molarity of ZnCl2 = ?

Solution:

First of all we will calculate the moles of Zn.

molar mass of zinc = 65.38 g/mol

number of moles = mass / molar mass

number of moles = 30 g/ 65.38 g/mol

number of moles = 0.4588 mole

From the balance chemical equation we will compare the moles of Zn and ZnCl2

     Zn    :   ZnCl2

     1       :      1

0.4588  :     0.4588

The number of moles of ZnCl2 are 0.4588 mol.

Molarity of ZnCl2:

Total volume of solution is 270 mL. We will convert it into liter.

1 L = 1000 mL

270/1000 = 0.27 L

Molarity =  moles of solute / volume of solution in liter

Molarity = 0.4588 mol / 0.27 L

Molarity = 1.699 mol/ L

The balanced chemical equation is

The conversions are  

Mass Zinc to moles Zinc (dividing by molar mass of Zinc)

Moles Zinc to moles  ( using mole ratio 1 : 1 )

Moles to Molarity of

(Answer)

1.71 M is the molarity of that forms when 30.0 g of zinc completely reacts with

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

the answer is the first option

explanation:

just googled it m8. not that hard

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