Chemistry, 01.10.2019 03:20 Pizzapegasus1

Asample of impure tin of mass 0.540 g is dissolved in strong acid to give a solution of sn2+. the solution is then titrated with a 0.0448 m solution of no3−, which is reduced to no(g). the equivalence point is reached upon the addition of 3.39×10−2 l of the no3− solution. find the percent by mass of tin in the original sample, assuming that it contains no other reducing agents.

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Asample of impure tin of mass 0.540 g is dissolved in strong acid to give a solution of sn2+. the so...