You mix 335 gallons of a mixture containing 4 wt% nacl (sodium chloride) and 96 wt% water (solution density = 1.0253 g/cm3) with an unknown volume of solution that is 26 wt% nacl and 74 wt% water (solution density = 1.1944 g/cm3). you want to produce a mixture containing 14 wt% nacl. find the volume of the second feed solution by following the steps below.

239.525 gallons

Explanation:

For the mass balance (which comes from Lavoisier rule), the initial mass of a compound must be equal to its final mass less its accumulation in a process. In a mixture, there is no accumulation, so:

(mNaCl)i = (mNaCl)f

Where i is the initial and f the final. For the initial mass, we have two different solutions and we must sum both masses. So, first let's calculate these masses:

mass of NaCl for solution 1:

1 gallon = 3785.41 cm³

335 gallon = 1.268x10⁶ cm³

So, the solution mass is equal to the density multiplied by the volume:

m = 1.0253x1.268x10⁶ = 1.30x10⁶ g

The mass of NaCl corresponds to 4% of the total mass, so:

mNaCl = 5.20x10⁴g

The mass of NaCl in the second solution will be 0.26m, where m is the total mass of the solution. So,

(mNaCl)i = 5.20x10⁴ + 0.26m

The final mass, is them sum of the initial ones, so it is 1.30x10⁶ + m, and the mass of NaCl in this solution must be

(mNaCl)f = 0.14x(1.30x10⁶ + m)

Then,

5.20x10⁴ + 0.26m = 0.14x(1.30x10⁶ + m)

0.26m - 0.14m = 1.82x10⁶ - 5.20x10⁴

0.12m = 1.30x10⁵

m = 1.083x10⁶ g

The volume of the solution is the mass divided by the density, so:

V = 1.083x10⁶/1.1944 = 9.067x10⁵cm³

V = 239.525 gallons

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.