Riley discovered pure gold has a density of 19.32 g/cm3.what would the volume for a piece of gold be if it had a mass of 318.97 g?

The volume for a piece of gold that has the mass of 318,67 g is 16,50cm3

Explanation:

Density = mass / volume

Volume = mass/ density

Volume = 318,97 g / 19,32 g/cm3 = 16,50cm3

The volume of a gold piece  is

Explanation:

Given:

Density of  pure gold,  

Mass of the gold piece,

To Find:

The volume for a piece of gold whose mass is  

Solution:

The formula for density is:

where,

D is density,

M is mass,  

V is volume.

The above formula can be rewriiten as

Substituting the values ,we get

Taking multiplicative inverse of density , we have

Result:

Thus the volume of gold piece weighing 318.97 g is

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer