Aballoon is filled with 35.0 l of helium in the morning when the temperature is 303 degrees kelvin. by 3: 00 p. m., the temperature has risen to 333 degrees kelvin. what is the new volume of the balloon?

2882 l

38.5 l

31.8 l

65.0 l

38.5 L

Explanation:

For this question, we can use

V1/T1=V2/T2

where

V1 (initial volume)= 35 L

T1 (initial temperature in Kelvin)= 303 K

V2(final volume)= ?

T2 (final temperature in Kelvin)= 333K

Since we are trying to find the final volume, we can rearrange the equation to say

V2= (V1/T1) × T2

V2= (35/303)×333

V2= 38.5 L

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