How many moles of solute particles are present in 7.94 ml of 0.887 m nano3? when you have your answer, take the log (base 10) of your answer and enter it with 2 decimal places.

The answer is 7.04278 x 10⁻³, and the log(10) is -2.15

Explanation:

In a 0.887 M NaNO₃ solution there are 0.887 mol in 1 liter of solution, We know that 1 L= 1000 ml, so we can calculate the number of mol which are in 7.94 ml as follows:

solute mol= 7.94 ml x 0.887 mol/ 1000 ml = 7.04278 x 10⁻³ mol

We take log(10) of 7.04278 x 10⁻³ and we obtain: -2.15

b) nuclear ive learned that in a pedtrodic table