How many milliliters of 2.19 m h2so4 are required to react with 4.75 g of solid containing 21.6 wt% ba(no3)2 if the reaction is ba2+ + so42- → baso4(s)? x ml

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% , thus,

Mass of = = 1.026 g

Molar mass of = 261.337 g/mol

The formula for the calculation of moles is shown below:

Thus,

Considering the reaction as:

1 moles of react with 1 mole of

Thus,

0.003926 mole of react with 0.003926 mole of

Moles of = 0.003926 mole

Also, considering:

Molarity = 2.19 M

So,

Volume = 0.0017927 L

Also, 1 L = 1000 mL

So, volume = 1.7927 mL

level 4 to level 2 : ))

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