The freezing point of ethanol, ch3ch2oh, is -117.300 °c at 1 atmosphere. kf(ethanol) = 1.99 °c/m

in a laboratory experiment, students synthesized a new compound and found that when 12.70 grams of the compound were dissolved in 216.5 grams of ethanol, the solution began to freeze at -117.431 °c. the compound was also found to be nonvolatile and a non-electrolyte.

what is the molecular weight they determined for this compound?

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

where,

= change in freezing point

= temperature of pure ethanol =

= temperature of solution =

= freezing point constant of ethanol =

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

Therefore, the molecular weight of this compound is 891.10 g/mol

the answer is c. nacl

1 is the answer to this problem