The nonvolatile, nonelectrolyte estrogen (estradiol), c18h24o2 (272.40 g/mol), is soluble in chloroform chcl3.

calculate the osmotic pressure generated when 13.5 grams of estrogen are dissolved in 181 ml of a chloroform solution at 298 k.

the molarity of the solution is ? m.
the osmotic pressure of the solution is ? atmospheres.

The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm

Explanation:

To calculate the molarity of the solution, we use the equation:

We are given:

Given mass of estrogen = 13.5 g

Molar mass of estrogen = 272.40 g/mol

Volume of solution = 181 mL

Putting values in above equation, we get:

Hence, the molarity of solution is 0.274 M

To calculate the osmotic pressure of the solution, we use the equation:

where,

= osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = 0.274 M

R = Gas constant =

T = temperature of the solution = 298 K

Putting values in above equation, we get:

Hence, the osmotic pressure of the solution is 6.70 atm

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

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i do not get it   at all