An aqueous solution of 1.29 m ethanol, ch3ch2oh, has a density of 0.988 g/ml. the percent by mass of ch3ch2oh in the solution is ? %.

6%

Explanation:

Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:

Now, the mass of the ethanol:

Finally, the by mass percent is:

%

%m=6%

Best regards.