Find the percent by mass of tin in the original sample, assuming that it contains no other reducing agents. a sample of impure tin of mass 0.528 g is dissolved in strong acid to give a solution of sn2+. the solution is then titrated with a 0.0448 m solution of no3−, which is reduced to no(g). the equivalence point is reached upon the addition of 4.03×10−2 l of the no3− solution.

Explanation:

The balanced equation for the given reaction is as follows.

Number of moles of consumed will be calculated as follows.

    No. of moles =

                          =

                          =

From the balanced equation,  we get to know that  2 moles of reacts with 3 moles of .

moles of reacts with M moles of .

        M =

            =

It is known that molar mass of tin is 118.71 g/mol. Hence, mass of Sn reacted will be as follows.

                 m =

                     =

So, percent mass of tin in the original sample =

                         =  

                         = 20.23 %

Thus, we can conclude that mass of tin is 20.23 %.

step-by-step explanation:

whole numbers, zero or greater

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