Using the correlation for the second virial coefficient (pitzer correlation), find the molar volume of 1-butanol vapour at 514 k and 10.4 bar, giving your answer to the nearest cm3/mol. the critical temperature is 563.1 k and the critical pressure of 1-butanol is 44.23 bar. take r = 8.314 j/mol-k and the acentric factor for 1- butanol as 0.594.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

lol for the pointsss

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.