Amixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 k and a total pressure of 100 kpa. if the vapour pressure of ethyl acetate at 303 k is 16 kpa, the molal saturation is (a) 0.080 (b) 0.087 (c) 0.264 (d) 0.029

Answer : The correct option is, (b) 0.087

Explanation :

The formula used for relative saturation is:

where,

= partial pressure of ethyl acetate

= vapor pressure of ethyl acetate

Given:

Relative saturation = 50 % = 0.5

Vapor pressure of ethyl acetate = 16 kPa

Now put all the given values in the above formula, we get:

Now we have to calculate the molar saturation.

The formula used for molar saturation is:

and,

P(vapor free) = Total pressure - Vapor pressure

P(vapor) = = 8 kPa

So,

P(vapor free) = 100 kPa - 8 kPa = 92 kPa

The molar saturation will be:

Therefore, the molar saturation is 0.087

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they are made of gases.

they have a spherical shape.

they make energy through fusion.