Chemistry, 24.09.2019 22:00 soccerjessie40901
A10 mm brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a) compute the hb of this material when a load of 1000 kg produced an indentation of 2.50|| mm in diameter. [1 mark] b) what will be the diameter of an indentation to yield a hardness of 300 hb when a 500-kg load is used?
Answers: 2
![\frac{2P}{\pi D [D - \sqrt{(D^{2} - d^{2})}]}](/tpl/images/0259/3590/c9ea6.png)
![\frac{2 \times 1000 kg}{3.14 \times 10 mm [D - \sqrt{((10 mm)^{2} - (2.50)^{2})}]}](/tpl/images/0259/3590/68716.png)
![\sqrt{(D^{2} - [D - \frac{2P}{HB} \pi D]^{2})}](/tpl/images/0259/3590/e427b.png)
![\sqrt{(10 mm)^{2} - [10 mm - \frac{2 \times 500 kg}{300 \times 3.14 \times 10 mm}]^{2}}](/tpl/images/0259/3590/4828f.png)
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A10 mm brinell hardness indenter is used for some hardness testing measurements of a steel alloy. a)...
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