Hexane and octane are mixed to form a 45 mol% hexane solution at 25 deg c. the densities of hexane and octane are 0.655 g/cm3 and 0.703 g/cm3, respectively. assume you have 1.0 l of octane. calculate the required volume of hexane. report your answer in liters.

The required volume of hexane is 0.66245 Liters.

Explanation:

Volume of octane = v=1.0 L=

Density of octane= d =

Mass of octane ,m=

Moles of octane =

Mole percentage of Hexane = 45%

Mole percentage of octane = 100% - 45% = 55%

Total moles = 11.212 mol

Moles of hexane :

Moles of hexane = 5.0454 mol

Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g

Density of the hexane,D =

Volume of hexane = V

(1 cm^3= 0.001 L)

The required volume of hexane is 0.66245 Liters.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.