Calculate the voltage of the cell: zn 1 zn2+ (10m) 11 cu2+(0.20m) 1 cu

The voltage of the cell is 1.05 V.

Explanation:

The given cell is:

Half reactions for the given cell follows:

Oxidation half reaction:

Reduction half reaction:

Net reaction:

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the of the reaction, we use the equation:

Putting values in above equation, we get:

To calculate the EMF of the cell, we use the Nernst equation, which is:

where,

= electrode potential of the cell = ?V

= standard electrode potential of the cell = +1.1 V

n = number of electrons exchanged = 2

Putting values in above equation, we get:

Hence, the voltage of the cell is 1.05 V.

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current