How many gram of nitrogen are needed to produce 325 gram of ammonia? n2(g) + 3h2(g) → 2nh3(g)

Answer : The mass of nitrogen needed are, 267.68 grams

Explanation :

Mass of = 325 g

Molar mass of = 17 g/mole

Molar mass of = 28 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of obtained from 1 mole of

So, 19.12 moles of obtained from moles of

Now we have to calculate the mass of .

Therefore, the mass of nitrogen needed are, 267.68 grams

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