Chemistry, 19.09.2019 03:30 itsgiovanna

The mass of a monoatomic gas can be computed from its specific heat at constant volume cv. (note that this is not cv.) take cv = 0.075 cal/g · c° for a gas and calculate (a) the mass of its atom and (b) the molar mass.

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Answer from: jasminemarie610

a) $6.6*10^{-23}g$

b) 39.74 g/mol

Explanation:

We have specific heat at constant volume $c_{V} = 0.075$ cal/g if the monoatomic gas behaves as ideal gas, we can know the molar specific heat at constant volume $C_{V}$ . For a monoatomical gas $C_{V}=\frac{3}{2} R$ with R the universal gas constant. So $C_{V}= \frac{3}{2} (1.987 \frac{cal}{mol*K})=2.9805 \frac{cal}{mol*K}[$ . We can calculate the heat with $c_{V}$ or $C_{V}$ as follows $Q= m c_{V} \Delta T = n C_{V} \Delta T$ with m: mass and n: number of moles. So we can solve that equation for the molar mass (M=m/n) obtaining $M = \frac{m}{n} = \frac{C_{V} }{c_{V} }$ . We can answer the question b) M=2.9805/0.075=39.74 g/molWith the molar mass and the avogadro's number ( $N_{Av}=6.022*10^{23}$ $mol^{-1}$ we can calculate the atom mass as follows $m_{atom} = \frac{M}{N_{Av} }$ Answer for the question a) is $m_{atom} =\frac{39.74}{6.022*10^{23} }=6.6*10^{-23}g$

Answer from: Quest

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

Answer from: Quest

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.

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The mass of a monoatomic gas can be computed from its specific heat at constant volume cv. (note tha...