Ablood sample with a known glucose concentration of 102.0 mg/dl is used to test a new at home glucose monitor. the device is used to measure the glucose concentration in the blood sample five times. the measured glucose concentrations are 96.3 , 97.2 , 104.8 , 111.5 , and 110.5 mg/dl. calculate the absolute error and relative error for each measurement made by the glucose monitor. a. 96.3 mg/dl absolute error = mg/dl relative error = b. 97.2 mg/dl absolute error = mg/dl relative error = c. 104.8 mg/dl absolute error = mg/dl relative error = d. 111.5 mg/dl absolute error = mg/dl relative error = e. 110.5 mg/dl

A. 96.3 mg/dL

Absolute error: 5.7 mg/dL

Relative error: 5.6%

B. 97.2 mg/dL

Absolute error: 4.8 mg/dL

Relative error: 4.7%

C. 104.8 mg/dL

Absolute error: 2.8 mg/dL

Relative error: 2.7%

D. 111.5 mg/dL

Absolute error: 9.5 mg/dL

Relative error: 9.3%

E. 110.5 mg/dL

Absolute error: 8.5 mg/dL

Relative error: 8.3%

Explanation:

The formula for the absolute error is:

Absolute error = |Actual Value - Measured Value|

The formula for the relative error is:

Relative error = |Absolute error/Actual value|

In your exercise, we have that

Actual Value = 102.0 mg/dL

A. 96.3 mg/dL:

B. 97.2 mg/dL

C. 104.8 mg/dL

D. 111.5 mg/dL

E. 110.5 mg/dL

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i'm assuming that the correct answer is indeed the first one/ "a"..