Ihave a 5 m stock solution of kci (for a protocol 100 mm kcl is considered "1x" concentration). if i want to make 10 ml of a 4x concentration kcl solution, how much 5 m stock and how much water do i need to add together?

You need 0.8 ml of 5M stock solution and you have to add 9.2 ml of water.

Explanation:

Protocol solution (1X): 100 mM=0.1M

4X: 0.4M

The concentration of a solution is inversely proportional to the volume of a solution, so:

where:

M1= 5M stock solution

V1= amount of solution we need to collect

M2=4X solution

V2= 10 ml (volumen of 4X solution)

Therefore:

5M×V1=0.4M×10ml

V1={0.4M}{5M}10ml=0.8ml

To make a 10 ml solution we have to add 9.2 ml of water because V2 es 10 ml.

i'm wiling to try and you : )

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