Achemist prepares a solution of potassium permanganate (kmno4) by measuring out 3.8 umol of potassium permanganate into a 100 ml volumetric flask and filling the flask to the mark with water. calculate the concentration in mol/l of the chemist's potassium permanganate solution. round your answer to 2 significant digits. x 5 ? explanation check

3,8×10⁻⁵ mol/L of potassium permanganate solution

Explanation:

To calculate concentration in mol/L you must convert the 3,8 umol to moles and 100 mL to liters, knowing 1 umol are 1×10⁻⁶mol and 1L are 1000 mL.

3,8 umol × (1×10⁻⁶mol / 1 umol ) = 3,8×10⁻⁶mol of potassium permanganate.

100 mL × ( 1L / 1000 mL) = 0,100 L

Thus, concentration in mol/L is:

3,8×10⁻⁶mol / 0,100 L = 3,8×10⁻⁵ mol/L of potassium permanganate solution

I hope it helps!

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explanation:

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