If 1.0 m hcl is added to an equal volume of 0.2 m naoh, what are the new concentrations of oh and h30+ ? select one: [h30*] = 0.8 m, [oh]= 1.3 x 10-14 m h30*] = 0.5 m, [oh]= 0.1 mi h30*] = 0.4 m, [oh]= 2.5 x 1014 m h30*] 1.0 m, [0h]= 0.2 m h30*] = 0.5 m, [oh]= 2.0 x 1014 m

[H3O+] = 0.4M and [OH-] = 2.5*10⁻¹⁴M

Explanation:

is a strong acid and is a strong base. The resulting reaction is a neutralization reaction forming and

From the given information,

1.0 M is added to an equal volume of 0.2 M

Let the volume of and be 25 ml each.

Moles of HCl  =

Moles of NaOH =

Therefore, moles of HCl remaining after mixing =

Total volume =

The new concentration of HCl =

Therefore, [H3O+] = 0.4M

"the periodic table is arranged in order of atomic number."

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