A41-g sample of potassium completely reacts with chlorine to form 78 g of potassium chloride. how many grams of chlorine must have reacted?

37.275g must react

Explanation:

Step 1: Balance the reaction

The reaction is as follow:

2 K + Cl2> 2KCl

This means that for 2 moles K we have 1 mole Cl2 ( and 2 moles KCl)

Step 2: Calculate moles

Moles of potassium:  moles = mass / Molar mass

Moles of potassium = 41g / 39.1g/mol  

Moles of potassium = 1.05 moles

for each 2 moles potassium we have 1 mole Cl2 ( and 2 moles KCl)

Moles of Chlorine : 1.05 / 2 = 0.525 moles ( and 1.05 moles of KCl)

Step 3: Calculate mass of chlorine

mass chlorine = moles x Molar mass  = 0.525 x 35.5 x 2

       = 37.275g Chlorine

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

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