ethylene glycol (antifreeze) has a density of 1.11 g/cm3. express your answer with the appropriate units.
a) what is the mass in grams of 376 ml of ethylene glycol?
b)what is the volume in liters of 3.10 kg of ethylene glycol?

Explanation:

Density of a substance is given by the mass of the substance divided by the volume of the substance .

Hence , d = m / V

V = volume

m = mass ,  

d = density ,

From the question , The density of ethylene glycol = 1.11 g / cm³

The unit  1 cm³ = 1 mL

Hence , density = 1.11 g / mL

( a )

The volume of ethylene glycol = 376 mL

The mass of ethylene glycol can be calculated by using the above formula -

d = m / V

m = d * V

m = 1.11 g / mL * 376 mL

m = 417.36 g

( b )

The mass of ethylene glycol = 3.10 Kg

( since , 1 Kg = 1000 g )

The mass of ethylene glycol = 3.10 Kg = 3.10 * 1000 = 3100 g

The Volume of ethylene glycol can be calculated by using the above formula -

d = m / V

V = m / d

V = 3100 g / 1.11 g / mL

V =  2792.79 mL = 2.79279 L

( since , 1 ml = 1/1000 L )

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne

im pretty sure its b