If you mix 10 ml of a 0.1 m hcl solution with 8 ml of
a0.2 m naoh solution, what will be the resulting ph?

The  pH of the resulting solution is 12.52.

Explanation:

n = number of moles

V = volume of the solution in Liters

1)1 mol of HCl gives 1 mol of hydrogen ion.

Concentration of the hydrogen ion = 0.1 M

Volume of the solution = 10 mL = 0.010 L

Moles of hydrogen ions =  = 0.001 mol

2) 1 mol of NaOH gives 1 mol of hydroxide ion.

Concentration of the Hydroxide ions = 0.2 M

Volume of the solution ,V'= 8 mL = 0.008 L

Moles of hydroxide ions ,n ' = 0.0016

1 mol of HCl neutralizes 1 mol of NaOH ,then 0.001 mol of HCl will neutralize 0.001 mol NaOH.

So left over moles of hydroxide ions in the solution will effect the pH of the solution:

Left over moles of hydroxide ions in the solution = 0.0016 mol - 0.0010 mol = 0.0006 mol

Left over concentration of hydroxide ions:

pH +pOH = 14

pH = 14 - 1.48 = 12.52

The  pH of the resulting solution is 12.52.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

2b2t

explanation:

2b2t