How much power (energy per unit time) can be provided by a 75 m high waterfall with a flow rate of 10,000 l/s? give answer in kw rate given here is volume per unit time; 10,000 l/s mean that every second 10,000 l of water go through the water fall

Explanation:

It is given that flow rate is 10,000 L/s. As 1 L equals 0.001 .

Hence, flow rate will be 10 . Calculate mass of water flowing per second as follows.

        Mass flowing per second = density × flow rate

                                                   =

                                                   =

Also, energy provided per second will be as follows.

                      E = mgh

Putting the given values into the above formula as follows.

                   E = mgh

                      =  

                       =

or,                    = 7350 kW

Thus, we can conclude that energy per unit time provided will be 7350 kW.