Given the densities of the following pure liquids, what volume of each is necessary to make 250 ml of a 350 mm solution? a. ethanol - 0.789 g/cm? b. acetone -0.791 g/cm c. formic acid - 1.220 g/cm3 d. tert-butylamine - 0.696 g/cm?

Answer :

(a) The volume of ethanol liquid needed are, 2.4 L

(b) The volume of ethanol liquid needed are, 1.9 L

(c) The volume of ethanol liquid needed are, 1.6 L

(d) The volume of ethanol liquid needed are, 1.7 L

Explanation : Given,

Volume of solution = 250 mL = 0.250 L   (1 l = 1000 mL)

Concentration of solution = 350 mM = 0.350 M    (1 mM = 0.001 M)

First we have to calculate the moles of solution.

(a)  For ethanol liquid :

To we have to calculate the mass of ethanol.

Now we have to calculate the volume of ethanol.

(b) For acetone liquid :

To we have to calculate the mass of acetone.

Now we have to calculate the volume of acetone.

(c) For formic acid liquid :

To we have to calculate the mass of formic acid.

Now we have to calculate the volume of formic acid.

(d) For tert-Butylamine liquid :

To we have to calculate the mass of tert-Butylamine.

Now we have to calculate the volume of tert-Butylamine.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.