Calculate the density of oxygen, o2, under each of the following conditions:
a) stp
b) 1.00 atm and 35.0°c
express your answers numerically in grams per liter. enter the density at stp first and separate your answers by a comma

a) 1.43 g/L

b) 1.27 g/L

Explanation:

Oxygen is an ideal gas, so, using the ideal gas equation:

PV = nRT  

Where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature (always in Kelvin!).

n = mass (m)/molar mass (MM), so:

PVMM = mRT

m/V is the density (d), so:

d =

R = 0.082 atm.L/(mol.K) and MM of O2 = 2x 16 = 32 g/mol

a) for STP, P = 1 atm and T = 0ºC = 273 K

d =

d = 1.43 g/L

b) P = 1 atm and T = 35ºC + 273 = 308 K

d =

d = 1.27 g/L

dynamic equilibrium is the answer.