What is the least amount of energy that can be emitted by an excited electron in a hydrogen atom falling from an excited state directly to the n = 3 state? what is the quantum number n for the excited state? humans cannot visually observe the photons emitted in this process. why not?

1.

2.

3. The associated wavelength belongs to the infrared spectrum which is invisible for humans.

Explanation:

Hello,

1. At first, according to the equation:

Whereas is the emitted energy, the first level energy, the atomic number, the first level and the second level. In such a way, the closest the 's are, the least the amount of emitted energy, therefore, (based on the statement) and , thus, the least amount of energy turns out being:

2. Secondly, and based on the first question, the quantum number for the excited state is mandatorily

3. Finally, to substantiate why we cannot observe the emitted photons we apply the following equation:

Whereas the obtained wavelength corresponds to the infrared spectrum which is not observable by humans.

Best regards.

it's filtration, but this is an assumption so my apologies if i got this