Acetone must be kept in a closed, pressure tank due to evaporation. acetone evaporates at a rate of 44 grams per minute left bracket startfraction g over min endfraction right bracket g min. if the tank holds 5454 pound-mass [lbm] of acetone and is allowed to remain open to the atmosphere, how many days [d] will it take for half of the acetone to evaporate?

20 days

Explanation:

We know that the rate of evaporation of acetone is 44 g/min, so let's transform the mass in gram

1 lbm = 453.592 g

545 lbm =

x = 2,473,893 g

So, half of this mass is 1,236,946.5 g

So, the time of evaporation will be

t = mass/rate of evaporation

t = 1,236,946.5/44

t = 28,112.42 min

One hour has 60 min, so

t = 28,112.42/60 = 468.54 hours

And one day has 24 hours, then

t = 468.54/24

t = 19.5 days

So, it'll be necessary 19 days and a part of another day to evaporate half of the acetone, so it'll be necessary 20 days.

6.4 cm (max) - 25 cm (min)