Se informa que un arco eléctrico estabilizado con agua llegó la temperatura de 25600 °f. en la escala absoluta, ¿cuál es la relación entre la temperatura y la de una llama de oxiacetileno (3500 °c)?

Explanation:

Translation:

It is reported that an electric arc stabilized with water reached the temperature of 25600 ° F. On the absolute scale, what is the relationship between the temperature and that of an oxyacetylene flame (3500 ° C)?

Solution:

Temperature of the electric arc = 25600°F

Temperature of the oxyacetylene flame = 3500°C

The absolute temperatures are usually recorded in Kelvin. In order to compare the two given temperatures, a need to convert to Kelvin arises.

From celcius to kelvin we have:

     K = 273.15 + T°C

T°C is the temperature in degree celcius

For the oxyacetylene flame:

     K = 273.15 + 3500 = 3773.15K

From fahrenheit to kelvin, we have:

    K = (T °F – 32) + 273.15

T °F is the temperature in degree fahrenheit

For the electric arc:

    K = (25600 – 32) + 273.15 = 14477.59K

We can see that by expressing the two temperature on the same absolute scale, an electric arc is by far hotter than an oxyacetylene flame.

the dependant variable is spilled water

the independent is the heat

answerto predict;