An impure sample of solid na₂co₃ is allowed to react with 0.1755 m hcl.

a 0.2337-g sample of sodium carbonate requires 15.55 ml of hcl solution. what is the purity of the sodium carbonate?

Thus percentage purity of sodium carbonate is 60.83%.

Explanation:

Volume of the HCl solution ,V = 15.55 mL= 0.01555 L

Concentration of HCl solution ,C= 0.1755 M

Moles of HCl in 0.1755 M solution = n

According o reaction 2 moles of HCl reacts with 1 mole of sodium carbonate.

Then n moles of HCl will react with:

of sodium carbonate.

Mass of of sodium carbonate:

Mass of the sample given= 0.2377 grams

Mass used up in reaction = 0.144585 g

percentage purity=

Thus percentage purity of sodium carbonate is 60.83%.