What will be the number of atoms in 0.750 gram of fe

8.085x10²¹ atoms

Explanation:

Atomic mass of Fe = 55.845 g/mol

it means ,

1 mole Fe = 55.845 g

1 mole = 6.02x10²³  atoms

so,

55.845g Fe has = 6.02x10²³ atoms

∴0.750 g  Fe has = {(6.02x10²³ x 0.750)/55.84} atoms

                             =8.085x10²¹ atoms

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

i think it's c. i'm not sure but i think so.