Iron(iii) oxide reacts with carbon monoxide according to the equation: fe2o3(s) + 3 co(g) → 2 fe(s) + 3 co2(g) a reaction mixture initially contains 22.95 g fe2o3 and 15.91 g co. assume that the reaction will progress to 100% completion. what mass (in g) of the excess reactant is leftover?

Explanation:

Hello,

In this case, the first step is to compute the moles of the reacting both iron (III) oxide and carbon monoxide as follows:

Now, we can take the reacting iron (III) oxide's moles in order to compute the actual consumed carbon monoxide's moles that would completely react with the iron (III) oxide's moles as follows:

Thus, since there are more available than consumed moles of carbon monoxide, we conclude that the iron (III) oxide is the limiting reagent, in such a way the leftover of carbon monoxide turns out into:

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here are some of the ways in which chemical and nuclear reactions differ.

explanation: