2hf(g)< > h2(g)+f2(g)
consider the reaction.
at equilibrium at 600 k, the concentrations are as follows.[hf] = 5.82 x 10^-2 m[h2] = 8.4 x 10^-3 m[f2] = 8.4 x 10^-3 mwhat is the value of keq for the reaction expressed in scientific notation? a. 2.1 x 10^-2b. 2.1 x 10^2c. 1.2 x 10^3d. 1.2 x 10^-3

Answer : The value of for the following reaction will be,

Explanation :

is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The given balanced equilibrium reaction is,

As we know that the concentrations of pure solids are constant that means they do not change. Thus, they are not included in the equilibrium expression.

The expression for equilibrium constant for this reaction will be,

Now put all the given values in this expression, we get :

Therefore, the value of for the following reaction will be,

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j