Apool is 44.6 m long and 27.6 m wide. if the average depth of water is 8.80 ft, what is the mass (in kg) of water in the pool? enter your answer in scientific notation.

3.30 × 10⁶ kg

Explanation:

The form of the pool may be approximated to a reactangular prism with height equal to the average depth of water.

1) Dimensions:

Length: 44.6 mWide: 27.6 mHeight: 8.80 ft

2) Volume formula

V = length × width × height

3) Unit conversions

Convert 8.80 ft to meters:

1 ft = 0.3048 m ⇒ 1 = 0.3048 m/ft8.80 ft × 0.3048 m/ft = 2.68 m

4) Volume calculation

Substitute the numbers in the formula:

V = length × width × height = 44.6 m × 27.6 m × 2.68 m ≈ 3,298.97 m³ ≈ 3,300 m³ (it is rounded to three significant digits)

5) Mass of water:

Density = mass / volume ⇒ mass = density × massDensity of water = 1,000 kg / m³mass = 3,300 m³ × 1,000 kg / m³ = 3,300,000 kg

6) Scientific notation

Choose the correct number of significant figures:

Since the three given factors have 3 significant figures, the correct number of significant figures of the volume and the mass is 3.

The mass must be expressed as a power of ten. The mantissa contains only the significant digits, and the number before the decimal point can only have one digit 1 through 9.

3,300,000 kg =  3.30 × 10⁶ kg

Coal i believe hope this

It is a mixture. simply put, a compound must be pure, that is, of only one chemical structure and composition. a mixture is made of different chemical substances (i.e. elements, molecules, compounds) that are not chemically bonded to each other, but instead physically grouped together, as in the case of gasoline (a homogeneous solution).