Uranium can be isolated from its ores by dissolving it as uo2(no3)2, then separating if as solid uo2(c2o4).3h2o. addition of 0.4031 gram of sodium oxalate, nac2o4,to a solution containing 1.481 gram of uranyl nitrate, uo2(no2)2, yields 1.073 gram of solid uo2(c2o4).3h2o
na2c2o4 + uo2(no3)2 3h2o ? uo2(c2o4).3h2o + 2nano3
determine the limiting reactant and the percent yield of this reaction

Limiting reactant: Na₂C₂O₄

Percent yield: 86.53%

Explanation:

Let's consider the following reaction.

Na₂C₂O₄ + UO₂(NO₃)₂ + 3H₂O → UO₂(C₂O₄).3H₂O + 2NaNO₃

The molar mass of Na₂C₂O₄ is 134.0 g/mol and the molar mass of UO₂(NO₃)₂ is 394.0 g/mol. In the balanced equation, there is 1 mole of each one.

The theoretical mass ratio of UO₂(NO₃)₂ to Na₂C₂O₄ is 394.0/134.0 = 2.940/1.

The experimental mass ratio of UO₂(NO₃)₂ to Na₂C₂O₄ is 1.481/0.4031 = 3.674/1.

Comparing the theoretical and the experimental mass ratios, we can see that the reactant in excess is UO₂(NO₃)₂ and the limiting reactant is Na₂C₂O₄.

We will use the limiting reactant to calculate the theoretical yield of UO₂(C₂O₄).3H₂O. The molar mass of UO₂(C₂O₄).3H₂O is 412.1 g/mol and the mass ratio of Na₂C₂O₄ to UO₂(C₂O₄).3H₂O is 134.0g / 412.1g.

The theoretical yield of UO₂(C₂O₄).3H₂O is:

0.4031 g Na₂C₂O₄ × (412.1 g UO₂(C₂O₄).3H₂O / 134.0 g Na₂C₂O₄) = 1.240 g UO₂(C₂O₄).3H₂O

The percent yield is:

(1.073 g / 1.240 g) × 100% = 86.53%

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

the answer is na (sodium)