Solution 1 consists of 80% benzene and 20% toluene. solution 2 consists of 30% benzene and 70% toluene. a) how many ml of solution 1 must be added to 500 ml of solution 2 in order to produce a solution that is 70% benzene? b) how many ml of solution 1 and how many ml of solution 2 must be combined to form a 100 ml solution that is 50% benzene and 50% toluene? c) is there a combination of solution 1 and solution 2 that is 90% benzene and 10% toluene?

Answer a) is 2000 mL solution 1.

Answer b) is 40 mL solution 1 and 60 mL solution 2.

Answer c)  isn't possible to produce a solution with 90% benzene and 10% toluene because is a percentage of benzene higher than the solution 1 and solution 2.

Explanation:

You can solve using an equation system base on the benzene percentage/ratio of each solution.

Answer a) X-> mL of solution 1

x*0.8+500*0.3=(500+ x)*0.7

x *0.8+500*0.3=500*0.7+ x*0.7

x*(0.8-0.7)=500*(0.7-0.3)

X*0.1=200

x=2000mL

Answer b) X-> mL of solution 1

x*0.8+(100-x)*0.3=(100)*0.5

x *0.8+100*0.3-x*0.3=50

x*(0.8-0.3)=50-30

x*(0.5)=20

x=40 mL

mL of solution 2=(100-x)=100-40=60 mL

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.

its first and third is your answer i did the qustion the fourth isnt right