What is the equilibrium constant for the reaction:
so2 (g) + no2 (g) â so3 (g) + no (g)
at 298 k? use the following data: r=8.314 j/(k. mol)
substance so2 (g) so3 (g) no2 (g) no (g)
îgo (kj/mol) -300.2 -371 51 86.6
a) 6.8 . 10-7
b) 1.5 . 106
c) 1.014
d) 0.986
e) -35.2

The correct answer is option b.

Explanation:

The equation used to calculate Gibbs free change is of a reaction is:  

The equation for the enthalpy change of the above reaction is:

We are given:

Putting values in above equation, we get:

To calculate the (at 298 K) for given value of Gibbs free energy, we use the relation:

where,

= Gibbs free energy = -35.2 kJ/mol = -35200 J/mol  (Conversion factor: 1kJ = 1000J)

R = Gas constant =

T =Temperature =298K[/tex]

= equilibrium constant at 298 k;

Putting values in above equation, we get:

Hence, correct answer is option b.