If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 k, and then the pressure is raised to 15 atm and the temperature is raised to 302 k, what will be the resulting volume of the gas

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

Given ,  

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

Solving for V₂ , we get:

V₂ = 15.04 mL

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.

rosa was looking for patterns to predict the products of chemical reactions. she recorded three similar decomposition reactions in the table.she should record 2licl + 3o2.

in the last row of the table. it is the thermal decomposition of chlorate lithium, hence, she should record these products as: lithium chloride ( 2licl ) and oxygen ( 3o2 )   2 > 2 licl + 3o2.