"a 0.2720 g sample of the acid ha, was titrated with standard sodium hydroxide, naoh, solution. determine the molecular weight of the acid if the sample required 45.00 ml of 0.1000 m naoh to neutralize."

60.44 g

Explanation:

45.00 mL x 0.1000 M NaOH x     1 mol HA    

                    1000 mL NaOH      1 mol NaOH

= 0.0045 mol HA

 0.2720 g HA  

0.0045 mol HA

= 60.44 g/mol

you did not give any options thus this is the best answer i can give to you with this little information you have given

> they are both natural and not man made

> they can be tracked and predicted by the right tools

-love shrooms